Predict the products of the reaction below. that is, complete the right-hand side of the chemical equation. be sure your equation is balanced and contains state symbols after every reactant and product. \chem; [h]\chem; [br](1[\chemwrong; [aq]]1)+[[\chem; [h]]_[2]]\chem; [o](1[\chemwrong; [l]]1)\chemarrow; []

The equation is as follow,

                                  HBr ₍aq₎  +  H₂O ₍l₎    →

Solution:
             HBr being strong acid with Ka value of 1.0 × 10⁹. When HBr is added to water, water acts as a base and HBr acts as a acid. Water picks the proton (H⁺) from HBr and converts into Conjugate acid (H₃O⁺) ahile HBr is converted into Conjugate Base (Br⁻) after loosing proton. The equation for this reaction is as follow,

                      HBr ₍aq₎  +  H₂O ₍l₎    →    H₃O⁺ ₍aq₎  +  Br⁻ ₍aq₎

Answer is to avoid experimental error