What is the concentration of the unknown h3po4 solution? the neutralization reaction ish3po4(aq)+3naoh(aq)→3h2o(l)+na3po 4(aq) -g, com?

The concentration of the unknown H₃PO₄ solution : 0.0344 M

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range

Titrations can be distinguished including acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases is used.

An acid-base titration there will be a change in the pH of the solution.

From this pH change a Titration Curve can be made which is a function of acid / base volume and pH of the solution

Acid-base titration formula

Ma, Mb = acid base concentration

Va, Vb = acid base volume

na, nb = acid base valence

We complete the possible questions

A 34.00 mL sample of an unknown H₃PO₄ solution is titrated with a 0.130 M NaOH solution. The equivalence point is reached when 26.98 mL of NaOH solution is added.

H₃PO₄ is a weak acid with valence 3 because it releases 3 H + atoms

H₃PO₄ -> 3H⁺ + PO₄⁻

NaOH is a strong base with valence 1 because it releases 1 OH- ions

NaOH ---> Na⁺ + OH-

We input the numbers into the formula:

M1.V1 n1= M2.V2 .n2

1 = H₃PO₄

2 = NaOH

M1.34 ml .3 = 0.130. 26.98 ml.1

M1 = 0.0344

So the molarity of the H₃PO₄ solution = 0.0344 M

the best tool to find the volume of that she needs to neutralize the acid

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Determine the endpoint of the titration.

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acid-base

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Identify the acids and the bases

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endpoint titration

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i'm pretty sure its b i might be wrong though!

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be