How many moles of cuso4 are used to make 250 ml of a 0.50 m cuso4 solution?

In order to prepare a 250 ml solution of CuSO₄ of 0.5 M we need to calculate the amount of CuSO₄ requires. So, as we know,

                      Molarity  =  Moles / Volume of Solution
Also, 
                      Molarity  =  (Mass ÷ M.mass) / Volume of Solution

Solving for Mass,

                      Mass  =  Molarity × M.mass × Volume

Putting Values,                                                  ∴ 250 ml  =  0.25 dm³
     
                      Mass  =  0.5 mol.dm⁻³ × 159.6 g.mol⁻¹ × 0.25 dm³

                      Mass  =  19.95 g

Step 2:
            Take 19.95 g of CuSO₄, add it to volumetric flask and add distilled water upto the mark of 250 ml. The resulting solution will be of concentration 0.5 M.

The answer is true for your question.

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic