Ireally need ! calculate the number of moles of al2 o3 that are produced when 0.60 mol of fe is produced in the following reaction. 2al(s) + 3feo(s) arrow 3fe(s) + al 2 o3 (s)a.0.20 molc.0.60 molb.0.40 mold.0.90 mol 

We use the mole ratio of aluminum oxide Al2O3 and iron Fe from their coefficients in the balanced chemical equation      
     2Al(s) + 3FeO(s) = 3Fe(s) + Al2O3(s)
which is one mole of aluminum oxide is to react with three moles of iron.  

Therefore, the number of moles of aluminum oxide is 
     moles of Al2O3 = 0.60 mol of Fe * 1 mol Al2O3 / 3 mol Fe
                                = 0.20 mol