What mass of water is in 150 g of mgso4×7h2o

The  mass  of  water  that is  in  150 g  of  Mgso4.7H20  is  calculated  as  follows

mass  of water=  molar  mass  of  H20  in  MgSO4.7H20  /total  molar mass  of  MgSO4.7H20    x mass ( 150g)

molar  mass of  h20 =   18  x 7=  126  g/mol  since  there  is 7 water  molecules
molar  mass  of MgSO4.7H20=  24 +  32 + (16x4)  +  (18x7)  =  246g/mol

Mass of water is therefore=  126  g/mol/246g/mol  x150g  =76.8 g

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