In part a, we saw that the theoretical yield of aluminum oxide is 0.700 mol . calculate the percent yield if the actual yield of aluminum oxide is 0.329 mol .

The  %  yield  is  calculated  as  follows

% yield  =  actual  yield/  theoretical  yield  x100

theoretical  yield  =   theoretical   moles  x  molar  mass
=  0.700  mole  x  101.96  g/mol  =  71.372  grams

actual  mass =   actual  moles  x  molar  mass
= 0.329 mol  x  101.96  =  33.545  grams

% yield  is therefore=   33.545/71.372  x100=  47%

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