When an airbag inflates, sodium azide, nan3, decomposes to produce sodium and nitrogen gas. how many molecules of nitrogen gas would be produced from 429 g of sodium azide?

The  number  of  nitrogen  gas  that   would   produced  from  429 g of  sodium  azide   is  calculated  as follows

write   the   equation  for  decomposition  of   sodium  azide

= 2NaN3  =  2 Na  +   3 N2

find  the  moles  of  NaN3   =moles  =  mass/molar  mass
=   429  g /65  g/mol  =   6.6  moles
by  use  of mole  ratio   between  NaN3  to  N2  which  is  2:3 the  moles  of  N2  is  therefore =  6.6  moles   x3/2 =  9.9  moles

then  by  use  of  Avogadro    law  constant
1mole  =  6.02  x10^23  molecules  what  about  9.9  moles

= 9.9  x(6.02  x10^23)  =  5.96  x10^24 molecules

What are the choices?