Gaseous methane ch4 will react with gaseous oxygen o2 to produce gaseous carbon dioxide co2 and gaseous water h2o . suppose 1.44 g of methane is mixed with 9.5 g of oxygen. calculate the maximum mass of water that could be produced by the chemical reaction. round your answer to 3 significant digits.

Answer : The maximum mass of produced will be,  3.24 grams

Explanation : Given,

Mass of = 1.44 g

Mass of = 9.5 g

Molar mass of = 16 g/mole

Molar mass of = 32 g/mole

Molar mass of = 18 g/mole

First we have to calculate the moles of and .

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 1 moles of react with 2 mole of

So, 0.09 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of .

As, 1 mole of react to give 2 moles of

So, 0.09 moles of react to give moles of

Now we have to calculate the mass of .

Therefore, the maximum mass of produced will be, 3.24 grams.