Determine the chemical formula for the compound, tetracarbonylplatinum(iv) chloride. [pt(co)4cl4] 2- [ptcl4](co)4 [pt(co)4]cl4 [pt(co)4cl4] 4- [pt(co)4]cl2

Analyze the Name of complex Compound.

                              Tetracarbonylplatinum(iv) chloride

So, there are,
                               4 Carbonyl groups = 4 CO = (CO)₄
                               1 Platinum Metal    = 1 Pt  = Pt
                               Unknown Chloride atoms = ?
In complexes positive part is always named first, so the sphere containing Pt and carbonyl ligands is written first,

                                     [Pt (CO)₄]

The charge on sphere is +4 because CO ligand is neutral, and Pt has a Oxidation state of four as written in name (IV),
So,
                                             [Pt (CO)₄]⁴⁺

Now, in order to neutralize +4 charge we should add 4 Chloride ions, So,

                                            [Pt (CO)₄] Cl₄

Hope you find the answer