The specific heat of water is 4.18 j/(g⋅∘c). calculate the molar heat capacity of water. express your answer to three significant figures and include the appropriate units.

Explanation:

It is known that relation between specific heat and molar heat capacity is as follows.

             Molar specific heat = Specific heat × Molar mass

It is given that specific heat of water is 4.18 . Now, we will calculate the molar mass water as follows.

      Molar mass of oxygen = 15.99 g/mol

      Molar mass of = g/mol = 2.00 g.mol

Hence, molar mass of = (15.99 + 2.00) g/mol

                                                    = 17.99 g/mol

Therefore, calculate the molar specific heat of water as follows.

              Molar specific heat = Specific heat × Molar mass

                                               =

                                               = 75.2    

Thus, we can conclude that the molar heat capacity of water is 75.2 .

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)