Using the heat equation q=mc∆t, what would the formula look like if we were solving for change in temperature? a mcq=∆t b q/mc= ∆t c qm/c=∆t d q m=∆tc give me a reason why and go into detail.

Avolleyball player hit a ball with a mass of 0.25 kg. the average acceleration of the ball is 15.5 m/s². how much force did the volleyball player apply to the ball? 62.0 n 3.87 n 62.0 m/s² 3.87 m/s²