How many liters of h2o are produces @ stp by the combustion of 30g of ch4 ch4+> co2 +2h2o

CH4+2O2———> CO2 +2H2O

M(CH4)=16.0 g/mol
30g CH4*1mol/16.0 g    - mol of CH4
30g CH4*(1mol/16.0 g)*(2 mol H2O/1 mol CH4) =15  mol H2O
30g CH4*(1mol/16.0 g)*(2 mol H2O/1 mol CH4)*22.4L/1mol=84 L H2O as gas, but at STP water should be liquid,so

15 mol H2O*18g H2O/1 mol=270g of H2O 
270g*1ml/1g= 270 ml =0.27 L of liquid water, in reality it should be like this, 
but I do not know what people who created this problem wanted H2O as liquid or as gas

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