In the combustion of propanol, what is the molar ratio of propanol (ch3ch2ch2oh) to co2? combustion of propanol: 2ch3ch2ch2oh + 9o2 → 6co2 + 8h2o

Propanol molecular formula is C₃H₇OH
the balanced reaction for combustion of propanol is as follows;
2C₃H₇OH + 9O₂ --> 6CO₂  + 8H₂O
Molar ratio of reactants to products can be found out by the stoichiometry.
By looking at the coefficients of reactants and products in the balanced reaction equation, molar ratio can determined.
Therefore the molar ratio of propanol to CO₂ is 2:6, simplified --> 1:3