How many atoms are in a sample of 68.7 g copper (cu)?

Divide the number of grams present in the sample by copper's gram atomic weight to find the number of gram atomic weights present. Then multiply that result by Avogadro's Number: 6.022137 x 10^23 atoms/gram atomic weight.1,200 g/(63.54 g/gram atomic weight) ? 18.885741 gram-atomic weights. Hope this helps. 

First convert grams into moles.
Then convert moles to atoms.

There are 63.546 grams of copper per mole. (This is just copper's atomic weight)
Thus, a 68.7 gram copper sample is (68.7/63.546) mols = 1.081 mols.

There are 6.022 * 10^23 atoms per mol.
6.022 * 10^23 * 1.081 = 6.52 * 10^23

Sorry i dont understand the question can you rephase it?