Chemistry, 27.07.2019 23:00 ramamullapudi3639

In a titration of 35.00 ml of 0.737 m h2so4, ml of a 0.827 m koh solution is required for neutralization.

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Answer from: oktacos

The reaction between H₂SO₄ and KOH is as follows;
2KOH + H₂SO₄ --> K₂SO₄ + 2H₂O
stoichiometry of KOH to H₂SO₄ is 2:1
the number of H₂SO₄ moles that have reacted = 0.737 M /1000mL x 35 mL
= 0.0258 mol
According to stoichiometry, number of KOH moles that have reacted at point of neutralization = number of H₂SO₄ moles x 2
Therefore number of KOH moles = 0.0516 mol
The molarity of KOH = 0.827 mol/L
The volume of 0.827 mol - 1 L
Therefore volume for 0.0516 mol - 1/0.827 x 0.0516 = 0.0624 L
volume of KOH needed = 62.4 mL

Answer from: Quest

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

Answer from: Quest

It is a mixture. simply put, a compound must be pure, that is, of only one chemical structure and composition. a mixture is made of different chemical substances (i.e. elements, molecules, compounds) that are not chemically bonded to each other, but instead physically grouped together, as in the case of gasoline (a homogeneous solution).

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