How many moles of lead (ii) hydroxide (solid) can be formed when 0.0225l of 0.135 m pb(no3)2 solution reacts with excess sodium hydroxide

Answer : The number of moles of lead(II)hydroxide are, 0.00304 mole

Explanation : Given,

Molarity of = 0.135 M = 0.135 mole/L

Volume of solution = 0.0225 L

First we have to calculate the moles of

Now put all the given values in this formula, we get the moles of

Now we have to calculate the moles of lead(II)hydroxide.

The balanced chemical reaction will be,

From the balanced chemical reaction, we conclude that

As, 1 mole of react to give 1 mole of

So, 0.00304 mole of react to give 0.00304 mole of

Therefore, the number of moles of lead(II)hydroxide are, 0.00304 mole