List the number of each type of atom on the right side of the equation pb(no3)2(aq)+2nacl(aq)→pbcl2(s)+2na no3(aq)

 The  number   of each  type  of atom  on the  right  side  of the equation

that is

Pb(No3)2(aq)  + 2 NaCl(aq)  =     PbCl2(s)   +2NaNo3(aq)

are    1  atom  of  Pb
          2 atoms of   N
          6 atoms  of    O
          2  atoms  of  Na
           2  atoms  of Cl

Explanation
In  Pb(NO3)2  there  is  1 x1=1  atoms  of  Pb,   1x2 =2  atoms   of N  and   3x2 =6  atoms of  O

In   NaCl  there is    2 x1= 2  atoms of Na  and  2 x1=2  atoms  of  Cl

Pb: 1 atom

Cl: 2 atoms

Na: 2 atoms

N: 2 atoms

O: 6 atoms

Explanation:

1) RighT side of the equation: PbCl₂(s)+2NaNO₃(aq)


2) The coefficients and subscripts tells the number of atoms in each chemical formula by this convention:


i) The coefficient before the compound (chemical formula) applies to all the elements to the right (in the very chemical formula).

ii) The subscripts to the right of the element apply only to the element to which it is subscripted.

ii) If there are parenthesis the subscrpts apply to all the elements inside the parenthesis.


3) With that, let's see each compound (chemical formula):


i) Pb Cl₂ (s): there are two kind of atoms, Pb and Cl.


Pb does not have any subscriPT, which is interpreted as subscript 1, so that is 1 atom of Pb.


Cl₂ means 2 atoms of chlorine


ii) 2NaNO₃:


Na: 2 atoms (because the coefficient)

N: 2 atoms (because the coefficient)

O: 6 atoms ( 2 x 3)