For the reaction a(g) 2 b(g), a reaction vessel initially contains only a at a pressure of pa = 1.32 atm. at equilibrium, pa = 0.25 atm. calculate the value of kp. (assume no changes in volume or temperature.)

A gaseous reaction at equilibrium is defined not only by its molarity but also by its partial pressure. Therefore the coefficient Kp for the given reaction is 18.32.

Given here,

The reaction,

1 mole of reactant  A forms 2 moles of product B.

The initial pressure of PA(i) = 1.32 atm

Pressure at equilibrium PA(equi) =  0.25 atm

At constant pressure and temperature

or

The initial pressure of the product

Put the values in the equation

Kp of the reaction can be calculated by the formula,

put the values

Therefore the coefficient Kp for the given reaction is 18.32.

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