2nh3(l) → nh4+(am) + nh2−(am) where (am) represents solvation by ammonia. at the boiling point (−33°c), kam = 5.1 × 10−27. calculate [nh4+] at this temperature.

What are the similarities between compounds and mixtures?

Why does ammonia, nh3, behave as a base when it reacts with an acid? z

The following questions a24 - a26 relate to 100 ml of 0.0150 m solution of benzoic acid (c6h3cooh). ka(c6h3cooh) = 6.4 x 10^-5. what is the ph of the solution after the addition of 1 x 10^-3 moles of naoh? you may assume no volume change to the solution upon addition of the naoh.