Complete the balanced overall ionic equation for lead(ii) nitrate dissolving in water. $$pb(no3)2(s)

The balanced overall ionic equation for leads (ii) nitrate dissolving in water:

Pb (NO₃) ₂ (s) → Pb²⁺ (aq) + 2NO₃⁻ (aq)

The electrolyte in the solution produces ions.

The equation of a chemical reaction can be expressed in the equation of the ions

For strong electrolytes (the ionization rate = 1) is written in the form of separate ions, while the weak electrolyte (degree of ionization <1) is still written as an un-ionized molecule

In the ion equation, there is an ion spectator that is the ion which does not react because it is present before and after the reaction

When these ions are removed, the ionic equation is called the net ionic equation

For gases and solids including water (H₂O) can be written as an ionized molecule

So only the dissolved compound is ionized ((expressed in symbol aq)

Ionic compounds consist of cations (ions +) and anions (ions -)

Lead (ii) nitrate, Pb (NO₃) ₂ is a solution (ion compound) which, if dissolved in water, ionizes into Pb2 + cation and NO3- anion

Pb (NO₃) ₂ (s) → Pb²⁺ (aq) + 2NO₃⁻ (aq)

The net ionic equation

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ion stability

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ionic bonding

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bcde is the incorrect answer it is a

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b