How many grams of calcium nitrate would react with 4.55 moles of chromium (iii) sulfate to produce calcium sulfate and chromium (iii) nitrate? a.) 6.86x10^2 g b.) 3.43x10^2 g c.) 6.04x10^-2 g d.) 3.09x10^3 g

The equation of the reaction is;
3Ca(NO3)2 + Cr2(SO4)3 = 3Ca(SO4) + 2 Cr(NO3)3
4.55 moles of chromium (iii) sulfate reacts with calcium nitrate
The mole ratio of Chromium (iii) sulfate to calcium nitrate is 1: 3
Therefore; the moles of calcium nitrate will be given by 
  = (4.55/ 1)×3
 = 13.65 moles
Hence; 13.65 moles of calcium nitrate would react with 4.55 moles of Chromium (iii) sulfate.