Be sure to answer all parts. what is the poh of 2.80 m ba(oh)2 solution? is the solution neutral, acidic, or basic? the poh of the solution is:

POH can be calculated by the negative logarithm of [OH⁻] .
pOH = -log [OH⁻]
pH scale is used to determine how acidic/ neutral or basic a solution is. By knowing the pOH the pH can be calculated, as;
pH + pOH = 14
pH = 14 - pOH
dissociation of Ba(OH)₂ is as follows;
Ba(OH₂) ---> Ba²⁺ + 2OH⁻ 
1 mol Ba(OH₂) dissociates into 2 OH⁻ moles
Therefore molarity of OH⁻ is twice as much as the molarity of  Ba(OH₂).
[OH⁻] = 2 x 2.80 M
        = 5.6 M
pOH = -log 5.6
         = -0.75
pH = 14 - - 0.75
     = 14.75
when the pOH is a negative value this means that the pH is greater than 14. 
Usually pH scale is from 1-14, with 1 being very acidic and 14 being very basic. Since pH is greater than 14 this means that the solution is strongly basic. 

Exothermic,  physical change after it is already baked

True is ur answer : )