Chemistry, 29.07.2019 13:30 bridgettebach

How many moles of baso4 are formed if 0.5 moles of na2 so4 react with 60 g of bacl2? na2 so4 + bacl2 → baso4 + 2nacl

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the balanced equation for the reaction is as follows
Na₂SO₄ + BaCl₂ > 2NaCl + BaSO₄
stoichiometry of Na₂SO₄ to BaCl₂ is 1:1
first we need to find out which the limiting reactant is
limiting reactant is fully used up in the reaction.

number of Na2So4 moles - 0.5 mol number of BaCl2 moles - 60 g / 208 g/mol = 0.288 mol
since molar ratio is 1:1 equal number of moles of both reactants should react with each other

therefore BaCl2 is the limiting reactant and Na2SO4 is in excess. amount of product formed depends on number of limiting reactant present.
stoichiometry of BaCl₂ to BaSO₄ is 1:1.

therefore number of BaSO4 moles formed - 0.288 mol

Answer from: alexmodersks3055

0.29

Explanation:

$Na_2SO_4+BaCl_2\rightarrow BaSO_4+2NaCl$

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\textMolar mass}}$

Putting values in above equation, we get:

$\text{Moles of}BaCl_2}=\frac{60g}{208g/mol}=0.29mol$

Moles of Na_2SO_4 = 0.5 moles

According to stochiometry, 1 mole of BaCl_2 reacts with 1 mole of Na_2SO_4

Thus 0.29 moles of BaCl_2 will react with 0.29 moles of Na_2SO_4

Thus BaCl_2 is the limiting reagent as it limits the formation of products and Na_2SO_4 is the excess reagent.

1 mole of BaCl_2 produces = 1 mole of BaSO_4

0.29 moles of BaCl_2 will produce= 0.29 moles of BaSO_4

Answer from: Quest

it should be all of them because it asks if you included all of those in your answer

explanation:

Answer from: Quest

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

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How many moles of baso4 are formed if 0.5 moles of na2 so4 react with 60 g of bacl2? na2 so4 + bacl...