When 10.0 ml of the 0.50 m solution is diluted to 100 ml as shown, what is the new concentration? ,

In this problem, we are asked to find the new concentration.

So, we use the dilution equation;

M1V1 = M2V2

Where M1 = concentration in molarity (moles/Liters) of the concentrated solution,

V2 =volume of the concentrated solution,

M2 =concentration in molarity of the dilute solution, and

V2 = volume of the dilute solution.

Before substituting the formula, convert the given mL to L since the unit for molarity is (moles/Liter).

Use the conversion factor (1000 mL = 1 L), so:

10.0 mL = 0.01 L

100 mL= 0.1 L

Now, we substitute the given (in liters) to the formula.

(0.50 M) (0.01 L) = M2(0.1 L)

M2 = [(0.50 M) (0.01 L)] / 0.1 L

M2 = 0.05 M

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.