The percent composition of methyl butanoate is 58.8% c, 9.8% h, and 31.4 % o and its molar mass is 102 g/mol. what is its empirical formula? what is its molecular formula? @mayankdevnani,

Given:
 C= 58.8% ,
H= 9.8% ,
and O=31.4 % 
 molar mass is = 102 g/mol. 

empirical formula=
58.8/C(12.01)= 4.9
 9.8/H(1.01)= 9.7
31.4/O(15.99)= 1.96

divide it by the least value so it is 1.96 which shows,
4.9/1.96= 2.5
9.7/1.96= 5
(C2.5H5O)2= C5H10O2

molecular formula= C10H20O4