In part a, you found the amount of product (3.00 mol p2o5 ) formed from the given amount of phosphorus and excess oxygen. in part b, you found the amount of product (2.60 mol p2o5 ) formed from the given amount of oxygen and excess phosphorus. now, determine how many moles of p2o5 are produced from the given amounts of phosphorus and oxygen. express your answer to three significant figures and include the appropriate units.

The correct answer is 2.60 moles.

Explanation:

The balanced equation is:  

4P + 5O₂ ⇒ 2P₂O₅

The number of moles of O₂, n = mass/molar mass

208 g / 32 g/mol = 6.5 mol

From the balanced equation,  

5 moles of O₂ reacts with 2 moles of P₂O₅

So, 6.5 moles of O₂ reacts with M moles of P₂O₅

M = 6.5 × 2/5

= 2.6 moles

Therefore, the required moles of P₂O₅ are 2.60 moles.  

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in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: