Achemist requires 0.446 mol na2co3 for a reaction. how many grams does this correspond to?

The amount of moles of Na₂CO₃ required = 0.446 moles
to find out the mass of Na₂CO₃ required, we need to find out its molar mass.
Molar mass is the mass of one mole of the element / compound. 
molar masses of the elements are as follows;
Na - 23 g/mol
C - 12 g/mol
O - 16 g/mol
Molar mass of Na₂CO₃ can be calculated as follows;
(Na *2 ) + C + (O *3)
(23*2) + 12 + (16*3)
= 46 + 12 + 48 
=106 g/mol
1 mol of Na₂CO₃ weighs - 106 g
Therefore 0.446 mol = 106 g/mol * 0.446 mol = 47.27g

668900 atoms in total