Shown below is a lewis structure of the formamidinium ion. what geometry is exhibited by the two nitrogens in the formamidinium ion?

The formamidinium ion structure is shown below.

A: trigonal planar

B: trigonal pyramidal

Explanation:

In the formamidinium ion, there are two nitrogen atoms, which are represented below by A and B. The geometry of a molecule is determined by the VSEPR theory, which states that the bonded electrons and the lone pairs of electrons intended to repulse to form a more stable compound.

Nitrogen has 5 electrons in its valence shell, so n the nitrogen A, there are 3 bonds (1 double bond and 2 simple bonds), and there are no lone pairs in the nitrogen atom (the central atom), thus the repulsive forces will be only by the bonds, and the geometry will be trigonal planar.

In nitrogen B, there are 3 simple bonds and one lone pair, which contributes to the repulsive forces, thus, the geometry must be trigonal pyramidal.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

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explanation: