What was the hiker's average velocity during part b of the hike? in part a, a hiker travels four kilometers east from nine to nine-forty-five a. m. in part b, a hiker travels six kilometers south from nine-forty-five to ten-forty-five a. m. in part c, a hiker travels four kilometers west from ten-forty-five to eleven-fifteen a. m. in part d, a hiker travels six kilometers north from eleven-fifteen a. m. to twelve p. m.

You have this in Chemistry. It should be in physics, but never mind that.

A

d = 4 km due east. See note for part B.

t =  45 minutes = 3/4 hour

v = ??

d = v * t

4 = v * (3/4)

v = 4/(3/4) = 4 * 4/3 = 16/3 = 5 1/3

So his rate of travel is 5 1/3 km/hr due east. If you do not give the direction when it says velocity, you are wrong. Velocity has direction.

B

10 45 to 11 45 is 1 hour.

d = v * t

d = 6 km due south (this is actually a displacement which also has direction). 

t = 1 hour

6 = v * (1)

6/(1) = v

6/(1) = v

v = 1 km/ hr due south