If a propane heater burns 38.95 g c3h8, it consumes 38.95 mol c3h8. 0.8830 mol c3h8. 1 mol c3h8. 44.10 mol c3h8.

               Option-2 (0.8830 mol C₃H₈) is the correct answer.

Solution:

                 In statement we are given with the amount of propane gas and are asked to find out the moles for given mass.

As we know mass is related to moles as follow,

                                      Moles = Mass / M.mass (1)

Data Given:

                Moles = ??

                Mass = 38.95 g

                M.mass = (C)3 + (H)8 = (12)3 + (1)8 = 36 + 8 = 44 g/mol

Putting values in equation 1,

                                    Moles = 38.95 g / 44 g/mol

                                    Moles = 0.8854 Moles

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.