Which of the following compounds has the highest boiling point? 2-pentanone pentene chloropentane pentane

chloropentane

Explanation:

When a hydrocarbon has a halogen atom, its properties will change because this group has a higher molecular weight and a higher polar moment that will be hard to defeat in order to reach the boiling point.

The Boiling point of the pentene is 30°C // pentane is 36,1°C //  2-pentanone is 101°C and chloropentane 108°C.

Simple hydrocarbons have lower boiling points compare with those with a functional group like the Oxygen in the 2-pentanone and the Chlorine in the  chloropentane. On the other heand,  Oxygen is not as electronegative and heavy like Chlorine, thus the chloropentane is the one with higher boiling point.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml