Part complete the first-order reaction, 2 n2o(g) → 2 n2(g) + o2(g), has a rate constant equal to 0.76 s-1 at 1000 k. how long will it take for the concentration of n2o to decrease to 32 % of its initial concentration?

  The  time  taken  for  the  concentration  of N2O  to  decrease  to  32%   of  its   initial   concentration  is  calculated  as  follows
  In(A1/A0)=-Kt
A1=  final  concentration  =  32/100=0.32
A0= initial   concentration  =100/1000=1
K= constant=  0.76  per  sec

time  is  therefore  calculated  as follows
In(0.32/1)=  -0.76 t
-1.1394  =-0.76t  divide  both  sid3es  by  -0.76
t  is  therefore=  1.5  s