Chemistry, 31.07.2019 15:30 jhunruh6247
The ka of benzoic acid is 6.4 x 10–5. what is the approximate ph of a 1.5 m solution of benzoic acid?
Answers: 1
is very very small the, the expression will be,
![[H^+]=c\alpha](/tpl/images/0154/8519/21a04.png)
![[H^+]=\sqrt{k_a\times c}](/tpl/images/0154/8519/881de.png)
![[H^+]=\sqrt{(6.4\times 10^{-5})\times 1.5}](/tpl/images/0154/8519/407b7.png)
![[H^+]=9.7\times 10^{-3}M](/tpl/images/0154/8519/1d5ea.png)
![pH=-log[H^+]](/tpl/images/0154/8519/15713.png)
![pH=-log[9.7\times 10^{-3}]=2.01](/tpl/images/0154/8519/353eb.png)
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The ka of benzoic acid is 6.4 x 10–5. what is the approximate ph of a 1.5 m solution of benzoic acid...
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