If a laboratory analysis of the mineral aegirine yields 10.0% na, 24.2% fe, 24.3% si, and 41.5% o, what is the empirical formula of the compound?

When determining empirical formulas the percentages are first divided by their respective molar masses
  Na (23 g/mol) Fe (56 g/mol)          Si (28 g/mol)        O (16 g/mol)
   10.0                          24.2%                          24.3%                    41.5 %
    10.0/23                         24.2/56                         24.3/28                      41.5/16
    =0.43                          =0.43                          = 0.86                         =2.59
divide all these values by the lowest fraction which is 0.43
0.43/0.43                         0.43/0.43                      0.86/0.43                 2.59/0.43
  =1                                  =1                                       =2                        =6.02
When we round  off these values the ratio of Na:Fe:Si:O = 1:2:6
therefore empirical formula would be NaFeSi2O6

Bis the answerhope it !