How much caco3 is produced if 47.5 moles nh3 are produced?

Answer is: 2380 grams of CaCO₃ is produced.
Chemical reaction: Ca(CN)₂ + 3H₂O → CaCO₃ + 2NH₃.
n(NH₃) = 47,5 mol.
From chemical reaction: n(CaCO₃) : n(NH₃) = 1 : 2.
n(CaCO₃) = 47,5 mol ÷ 2.
n(CaCO₃) = 23,75 mol.
m(CaCO₃) = n(CaCO₃) · M(CaCO₃).
m(CaCO₃) = 23,75 mol · 100,09 g/mol.
m(CaCO₃) = 2380 g.

It would be (at) + cu (s)

They carry out the exchange of gases as we breathe ( oxygen and carbon dioxide).