Asample of gas has a pressure of 3.6 atmospheres at a temperature of 301 kelvin. what would be the pressure of the same sample of gas when the temperature is decreased to 285 kelvin? show all of the work used to solve this problem.

Answer is: pressure is 3,40 atm
Gay-Lussac's Law states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature.
p₁/T₁ = p₂/T₂.
p₁ = 3,6 atm.
T₁ = 301 K.
p₂ = ?.

T₂ = 285 K.

3,6 atm/301 K = p₂/285 K.
3,6 atm · 285 K = 301 K · p₂.

p₂ = 1026 atm · K ÷ 301 K.

p₂ = 3,4 atm

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