Which salt is not derived from a strong acid and a strong soluble base? 1. liclo4 2. csbr2 3. mgcl2 4. ba(no3)2 5. nai?

I believe the answer is MgCl, this is because the bases of group one elements (alkali metals) such as sodium, lithium , and cesium, are all strong bases unlike those of group 2 and group 3. The bases of group one elements ( NaOH, LiOH, CsOH) all readily dissolve in water forming strong soluble base. Then between a base of Ba (Ba(OH)2)and that of Mg, (Mg(OH)2), the one for Ba is more stronger because Ba is more reactive than that of Mg because it is not readily dissolve in water ( less soluble in water to give OH- ions)

3. MgCl2 For each salt, determine what acid and base were used to create it by separating the salt into it's cation and anion. From there, determine the acid and base used to create the salt by adding the appropriate number of hydroxyl group(s) to the cation and hydrogen to the anion. So: LiClO4 -> Li, ClO4 -> LiOH + HClO4. LiOH is a strong base, and HClO4 is a strong acid. CsBr2 -> Cs, Br2 -> CsOH + HBr2 CsOH is a strong base, and HBr2 is a strong acid. MgCl2 -> Mg, Cl2 -> Mg(OH)2 + HCl Mg(OH)2 is not a strong soluble base HCl is a strong acid. Therefore MgCl2 is the correct salt. Ba(NO3)2 -> Ba, NO3 -> Ba(OH)2 + HNO3 Ba(OH)2 is a strong base, and HNO3 is a strong acid. NaI -> Na, I -> NaOH + HI NaOH is a strong base, and HI is a strong acid.

m=9

step-by-step explanation:

7m+8=71 subtract   8 from 71 which is 63 than divide it by 7m   equal 9.