What is the net ionic equation of the reaction of naoh with acetic acid?

First, check the standard equation: 
CH3COOH+NaOH→H2O+CH3COONa 
The ionic equation for the above: 
CH3COOH(aq)+Na+(aq)+OHâ’(aq)→ 
CH3COOâ’(aq)+Na+(aq)+H2O(l) 
Therefore, the net ionic equation is (remove the Na+ as it is present as both a reactant and a product): 
CH3COOH(aq)+OHâ’(aq)→ 
CH3COOâ’(aq)+H2O(l) 
(note the charge on both sides has to be the same, in this case 1.

D-no effect on the rate

Which of the following did you identify correctly