Given the equation representing a reaction at equilibrium:
n2(g) + 3h2(g) < ==> 2nh3(g)
what occurs when the concentration of h2(g) is increased?
(1) the equilibrium shifts to the left, and the concentration of n2(g) decreases.
(2) the equilibrium shifts to the left, and the concentration of n2(g) increases.
(3) the equilibrium shifts to the right, and the concentration of n2(g) decreases.
(4) the equilibrium shifts to the right, and the concentration of n2(g) increases.

try answer.com that works for me

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.