The average dosage of oxcarbazepine for an epileptic child between the ages of 4 and 16 is 9.00 mg per 1 kg of body weight (9.00 mg/kg). calculate how many milliliters of oxcarbazepine a child who weighs 47.3 pounds should be prescribed considering the medication is served as a suspension of 60.0 mg/ml. keep in mind that 1 pound is equivalent to 0.453 kilograms. express your answer to three significant figures.

The term gas is limited to those substances that exist in the gaseous state at

1.) which of the following is a molecule but not a compound? a.he b.f2 c.h2o d.ch4 2.) what is a physical combination of substances? a.a compound b.a molecule c.a mixture d.an element 3.) what is a chemical combination of substances? a.a compound b.an atom c.a mixture d.an element 4.) what is the relationship between the solute and solvent in a solution? a.they form a compound b.they form a mixture c.they form molecules d.they form chemical bonds 5.) the gases in air dissolve in water. what would be one way to reduce the amount of a gas dissolved in water? a.add more water b.reduce the air pressure c.increase the air pressure d.stir the water 6.) how would you determine the solubility of a substance? a.find how well it dissolved various substances. b.find the mass and the volume of the substance. c.find the temperature at which the substance evaporated. d.find how much i was able to dissolve in a solute. 7.) the periodic table organizes all of the kinds of a.molecules. b.compounds. c.atoms. d.ions. 8.)what distinguishes two substances combined to become a compound vs. two substances combined to become a mixture? a.whether they can be easily separated b.whether they chemically bond together c.whether they both are visible d.whether they are heterogeneous 9.) the principle components of air are: n2 78% o2 21% ar 0.95% co2 0.038% this is a solution of a.molecules and atoms. b.molecules. c.compounds and molecules. d.atoms.

Which of the following represents the balanced reduction half-reaction from the redox reaction? (2 points) pb + pd(no3)2 yields pb(no3)2 + pd pb yields pd2+ + e- pd2+ + 2e- yields pd pb + e- yields pb 2 pd2+ + 4 e- yields 2 pd