Amole of any substance contains avogadro's number of units.
a. write an equivalence statement for this definition.
b. write the possible conversion factors from this relationship.
c. to determine the following, tell which conversion factor you would need to use:
• moles al from atoms al
• atoms au from mol au

a. "one mole of any substance has 6.022x10²³ atoms, molecules or ions (Avogadro's number) into it"

b.  and

c.

•

•  

Explanation:

Hello,

a. In this case, a plausible statement would be: "one mole of any substance has 6.022x10²³ atoms, molecules or ions (Avogadro's number) into it".

b. Now, the possible conversion factors could be:

or conversely:

c.

• Moles Al from atoms Al: the conversion factor will be:

Since we will need to simplify moles to get atoms.

• Atoms Au from mol Au: the conversion factor will be:

Since we will need to simplify atoms to get moles.

Best regards.

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years

if the temperature drops and becomes cool

then the atmosphere can be freezing as the water vapor in the air is at maximum (100%) and can be severely cold

also can be snowing lightly as the moisture in the air will start to solidify

and btw this is not chemistry but