The combustion of 14 grams of co, according to the reaction co(g) + ½o2(g) → co2(g) + 67.6 kcal, gives off how much heat?

The amount of heat released by the combustion of 14 g of CO is 33.8 kCal

Explanation:

To calculate the number of moles, we use the equation:

Given mass of CO = 14 g

Molar mass of CO = 28 g/mol

Putting values in above equation, we get:

The chemical reaction for the combustion of CO follows the equation:

By Stoichiometry of the reaction:

If 1 mole of CO produces 67.6 kCal of heat

Then, 0.5 moles of CO will produce = of heat.

Hence, the amount of heat released by the combustion of 14 g of CO is 33.8 kCal

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.