Gef3h is formed from geh4 and gef4 in the combination reaction: geh4 + 3gef4 -> 4gef3h. if the reactiln yield is 92.6%, how many moles of gef4 are needed to produce 8 mol of gef3h?

Answer : The number of moles of needed to produce 8 mole of are, 6.48 moles.

Explanation :

The given balanced chemical reaction is:

First we have to calculate the moles of

From the balanced chemical reaction we conclude that,

As, 4 moles of produced from 3 mole of

So, 8 moles of produced from mole of

Now we have to calculate the moles of when the reaction yield is 92.6 %.

As, 92.6 % yield produced from 6 moles of

So, 100 % yield produced from moles of

Therefore, the number of moles of needed to produce 8 mole of are, 6.48 moles.

some sources quote the lethal dose, for an average 170lbs opiate-naive individual is between 75 and 375 mg

the answer is 0.8m.

by: nicholas