100 g of water (specific heat =4.184j/g) and 100g of a metal sample (specific heat = 0.397 j/g) are heated from 25 to 75. which substance required more thermal energy to reach 75? (explain your reasoning).

Q=heat and Q=m*c*dekta(temp)
So we have

Q= 100g*4.184*50=20920J of heat energy

Q= 100g * 0.397* 50= 1985J of heat energy

So the water requires more energy and this is due to the higher heat capacity value of water than the metal sample

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True, the standard unit for volume is liters which can be represented by either a lower case "l" or a capital "l"