Chemistry, 04.08.2019 02:00 naydiag

When an ionic bond forms, which part(s) of the atoms are directly involved?

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Answer from: chad65

The outermost electrons of the atom form ionic bonds.
There are three distinct parts of every atom, the protons, and neutrons that make the core of the atom and the electrons that orbit the core.
All atoms aim to achieve the configuration of their electron orbits like the ones found in noble gases such as helium.
The ionic bond is formed between ions, charged atoms, usually between a metal like sodium and a non-metal like chlorine.
A metal in an ionic bond donates an electron to achieve a stable configuration and the non-metal atoms accept an electron to their outer-most orbit to do the same. These atoms now become ions or charged atoms. Due to a loss of an electron, the metal now becomes positive, and the non-metal becomes negative due to the presence of an addition electron with a negative charge in its structure. This difference in charges attracts the two ions to each other and makes them form an ionic bond.

Answer from: Quest

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

Answer from: Quest

Okay this will take 1 hour okay dont forget me.

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