Ahydrogen atom contains a single electron that moves in a circular orbit about a single proton. assume the proton is stationary, and the electron has a speed of 7.8 105 m/s. find the radius between the stationary proton and the electron orbit within the hydrogen atom.

To answer this, one must simplify and rearrange the formula for force in a circular motion: (me(v^2)/y) = (k9^2/r^x). Rearranged for Radius is: r = (k9^2)/(me(v^2)). Based on the conditions this gives you: r = (9*(10^9)x*((1.5*10^-19)^2)) / (9*(1*10^-31)*((7.8*(10^5))^2)). This will give you 4.161 * (10^-10) = 4.161 A

Sorry i dont understand the question can you rephase it?