How many grams of water can be produced when 8.73 moles of benzene (c6h6) react with excess oxygen? unbalanced equation: c6h6 + o2 → co2 + h2o show, or explain, all of your work along with the final answer.

2 C6H6 + 15 O2 = 12 CO2 + 6 H2O
2 moles C6H6 6 moles H2O8.73 moles C6H6 ( moles H2O)
( moles H2O) = 8.73 x 6 / 2
( moles H2O) = 52.38 / 2
= 26.19 moles of H2O
Molar mass H2O = 18.00 g/mol
1 mole 18.00 g26.19 moles ( mass of H2O)
mass of H2O = 26. 19 x 18.00 => 471.42 g of water
hope this helps!

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