How many atoms of each element are present in 3.2 moles of k2so3

- atoms of K, atoms of S and atoms of O.

Solution:- We have 3.2 moles of . Looking at it's molecular formula, it has two K, one S and three O. It means, 1 mole of the compound has two moles of K, one mole of S and 3 moles of O.

Now we could calculate the moles of each present in 3.2 moles of the compound as..

So, moles of K = 3.2 mol of compound x (2 mol K/mol of compound) = 6.4 mol K

moles of S = 3.2 mol of compound x (1mol S/1mol compound) = 3.2 mol S

moles of O = 3.2 mol of compound x (3 mol O/1mol compound) = 9.6 mol O

Now to convert the moles of each to atoms, we multiply by Avogadro number.

atoms of K = 6.4 mol x (6.022 x 10^23 atoms/1mol) = atoms of K

atoms of S = 3.2 mol x (6.022 x 10^23 atoms/1mol) = atoms of S

atoms of O = 9.6 mol x (6.022 x 10^23 atoms/1mol) = atoms of O

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.

answer; talc and gypsum;