The reaction of hydrazine (n2h4) with chlorine trifluoride (clf3) has been used in experimental rocket motors. n2h4(g) + 4/3 clf3(g) 4 hf(g) + n2(g) + 2/3 cl2(g) (kp) how is the equilibrium constant, kp, for this reaction related to kp' for the reaction written this way?

Answer is: the equilibrium constant is (Kp)³ = Kp'.
N₂H₄(g) + 4/3ClF₃(g) → 4HF(g) + N₂(g) + 2/3Cl₂(g) (Kp).
3N₂H₄(g) + 4ClF₃(g) → 12HF(g) + 3N₂(g) + 2Cl₂(g) (Kp').
Second reaction was multiply with 3. The equilibrium constant is a ratio of the concentration of the products to the concentration of the reactants.

The answer is b metal denting

You would do 1500/4 and the answer is 375