A50.0 g gold spoon at 10.0 °c is placed in a cup of how water 95.0 °c. how much heat does the water lose to the spoon if the spoon reaches a temperature of 59.0 °c?

The water lost 313.6 J of heat to the spoon

Temperature is one of the principal quantities that shows the degree of heat or cold from an object / space

Temperature is used as a guide to the level of heat energy from objects

Temperature cannot be measured by the surface of the hand because it is not accurate but can be measured by a thermometer. Temperature units include Celsius, Fahrenheit, Reamur or Kelvin

Whereas heat is a form of energy that can flow from high-temperature objects to low-temperature objects.

So heat moves when there is a difference in temperature and can increase or decrease the temperature. An object that receives a lot of heat will cause a large increase in temperature

The amount of heat is influenced by the mass of the object and the difference in temperature

Can be formulated

Q = m.c.ΔT

Q: heat received or removed by an object (J)

m: object mass (kg)

c: heat type substance (J / kg⁰C)

ΔT: temperature change (⁰C)

When A 50.0 g of gold spoon at 10.0 ° c is placed in a cup of hot water 95.0 ° c. Heat balance occurs:

q lost = q gain

q lost from water = q gain from spoon

q lost from water = m. cp (gold). delta t

The specific heat of gold is 0.128 J / g ° C.

q lost from water = 50 g. 0.128. (59-10)

q lost from water = 313.6 J

heat and temperature

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grams of water

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decrease heat transfer between two objects

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Keywords: heat gain, heat lost

the answer is learned

periodic trends is an atom that gets larger as the number of electronic shells increase, the radius of atoms increases as you go down a certain group in the periodic table of elements. in general, the size of an atom will decrease as you move from left to right of a certain period.